if so, skip it and return.n for competing_l, competing_g of optimal.g[k]n continue if competing_l > ln return if competing_g <= gn # this sequence might be part of the final optimal sequence.n optimal.g[k][l] = gn optimal.m[k][l] = mn optimal.pi[k][l] = pinn # helper: evaluate bruteforce matches ending at k.n bruteforce_update = (k) =>n # see if a single bruteforce match spanning the k-prefix is optimal.n m = make_bruteforce_match(0, k)n update(m, 1)n for i in [1..k]n # generate k bruteforce matches, spanning from (i=1, j=k) up to (i=k, j=k).n # see if adding these new matches to any of the sequences in optimal[i-1]n # leads to new bests.n m = make_bruteforce_match(i, k)n for l, last_m of optimal.m[i-1]n l = parseInt(l)n # corner: an optimal sequence will never have two adjacent bruteforce matches.n # it is strictly better to have a single bruteforce match spanning the same region:n # same contribution to the guess product with a lower length.n # --> safe to skip those cases.n continue if last_m.pattern 'bruteforce'n # try adding m to this length-l sequence.n update(m, l + 1)nn # helper: make bruteforce match objects spanning i to j, inclusive.n make_bruteforce_match = (i, j) =>n pattern: 'bruteforce'n token: password[i..j]n i: in j: jnn # helper: step backwards through optimal.m starting at the end,n # constructing the final optimal match sequence.n unwind = (n) =>n optimal_match_sequence = []n k = n - 1n # find the final best sequence length and scoren l = undefinedn g = Infinityn for candidate_l, candidate_g of optimal.g[k]n if candidate_g < gn l = candidate_ln g = candidate_gnn while k >= 0n m = optimal.m[k][l]n optimal_match_sequence.unshift mn k = m.i - 1n l--n optimal_match_sequencenn for k in [0...n]n for m in matches_by_j[k]n if m.i > 0n for l of optimal.m[m.i - 1]n l = parseInt(l)n update(m, l + 1)n elsen update(m, 1)n bruteforce_update(k)n optimal_match_sequence = unwind(n)n optimal_l = optimal_match_sequence.lengthnn # corner: empty passwordn if password.length 0n guesses = 1n elsen guesses = optimal.g[n - 1][optimal_l]nn # final result objectn password: passwordn guesses: guessesn guesses_log10: @log10 guessesn sequence: optimal_match_sequencenn # ------------------------------------------------------------------------------n # guess estimation -- one function per match pattern ---------------------------n # ------------------------------------------------------------------------------nn estimate_guesses: (match, password) ->n return match.guesses if match.guesses? ': ['`~', null, null, '2@', '', null], '': [null, '1! ': ['lL', '[{', ']}', '=+', '-_', 'sS'], '@': ['1! ': [',<', '3#', '4$', 'pP', 'eE', 'oO'], '/': ['lL', '[{', ']}', '=+', '-_', 'sS'], '0': ['9(', null, null, '[{', 'lL', 'rR'], '1': ['`~', null, null, '2@', '', null], '2': ['1! ', '0'], '4': [null, null, '7', '8', '5', '2', '1', null], '5': ['4', '7', '8', '9', '6', '3', '2', '1'], '6': ['5', '8', '9', '+', null, null, '3', '2'], '7': [null, null, null, '/', '8', '5', '4', null], '8': ['7', null, '/', '*', '9', '6', '5', '4'], '9': ['8', '/', '*', '-', '+', null, '6', '5']}n mac_keypad: {'*': ['/', null, null, null, null, null, '-', '9'], '+': ['6', '9', '-', null, null, null, null, '3'], '-': ['9', '/', '*', null, null, null, '+', '6'], '. l_max is the maximum optimaln # sequence length spanning each prefix of the password. ', null, null]}n dvorak: {'! ', null, null, '3#', 'wW', 'qQ'], '3': ['2@', null, null, '4$', 'eE', 'wW'], '4': ['3#', null, null, '5%', 'rR', 'eE'], '5': ['4$', null, null, '6^', 'tT', 'rR'], '6': ['5%', null, null, '7&', 'yY', 'tT'], '7': ['6^', null, null, '8*', 'uU', 'yY'], '8': ['7&', null, null, '9(', 'iI', 'uU'], '9': ['8*', null, null, '0)', 'oO', 'iI'], ':': ['lL', 'pP', '[{', '', '/? (% instead of 5, A instead of a. )1+$/n lastIndex = 0n while lastIndex < password.lengthn greedy.lastIndex = lazy.lastIndex = lastIndexn greedy_match = greedy.exec passwordn lazy_match = lazy.exec passwordn break unless greedy_match?n if greedy_match[0].length > lazy_match[0].lengthn # greedy beats lazy for 'aabaab'n # greedy: [aabaab, aab]n # lazy: [aa, a]n match = greedy_matchn # greedy's repeated string might itself be repeated, eg.n # aabaab in aabaabaabaab.n # run an anchored lazy match on greedy's repeated stringn # to find the shortest repeated stringn base_token = lazy_anchored.exec(match[0])[1]n elsen # lazy beats greedy for 'aaaaa'n # greedy: [aaaa, aa]n # lazy: [aaaaa, a]n match = lazy_matchn base_token = match[1]n [i, j] = [match.index, match.index + match[0].length - 1]n # recursively match and score the base stringn base_analysis = scoring.most_guessable_match_sequence(n base_tokenn @omnimatch base_tokenn )n base_matches = base_analysis.sequencen base_guesses = base_analysis.guessesn matches.pushn pattern: 'repeat'n i: in j: jn token: match[0]n base_token: base_tokenn base_guesses: base_guessesn base_matches: base_matchesn repeat_count: match[0].length / base_token.lengthn lastIndex = j + 1n matchesnn MAX_DELTA: 5n sequence_match: (password) ->n # Identifies sequences by looking for repeated differences in unicode codepoint.n # this allows skipping, such as 9753, and also matches some extended unicode sequencesn # such as Greek and Cyrillic alphabets.n #n # for example, consider the input 'abcdb975zy'n #n # password: a b c d b 9 7 5 z yn # index: 0 1 2 3 4 5 6 7 8 9n # delta: 1 1 1 -2 -41 -2 -2 69 1n #n # expected result:n # [(i, j, delta), ...] = [(0, 3, 1), (5, 7, -2), (8, 9, 1)]nn return [] if password.length 1nn update = (i, j, delta) =>n if j - i > 1 or Math.abs(delta) 1n if 0 < Math.abs(delta) <= @MAX_DELTAn token = password[i..j]n if /^[a-z]+$/.test(token)n sequence_name = 'lower'n sequence_space = 26n else if /^[A-Z]+$/.test(token)n sequence_name = 'upper'n sequence_space = 26n else if /^d+$/.test(token)n sequence_name = 'digits'n sequence_space = 10n elsen # conservatively stick with roman alphabet size.n # (this could be improved)n sequence_name = 'unicode'n sequence_space = 26n result.pushn pattern: 'sequence'n i: in j: jn token: password[i..j]n sequence_name: sequence_namen sequence_space: sequence_spacen ascending: delta > 0nn result = []n i = 0n last_delta = nullnn for k in [1...password.length]n delta = password.charCodeAt(k) - password.charCodeAt(k - 1)n unless last_delta?n last_delta = deltan continue if delta last_deltan j = k - 1n update(i, j, last_delta)n i = jn last_delta = deltan update(i, password.length - 1, last_delta)n resultnn #-------------------------------------------------------------------------------n # regex matching ---------------------------------------------------------------n #-------------------------------------------------------------------------------nn regex_match: (password, _regexen = REGEXEN) ->n matches = []n for name, regex of _regexenn regex.lastIndex = 0 # keeps regex_match statelessn while rx_match = regex.exec passwordn token = rx_match[0]n matches.pushn pattern: 'regex'n token: tokenn i: rx_match.indexn j: rx_match.index + rx_match[0].length - 1n regex_name: namen regex_match: rx_matchn @sorted matchesnn #-------------------------------------------------------------------------------n # date matching ----------------------------------------------------------------n #-------------------------------------------------------------------------------nn date_match: (password) ->n # a 'date' is recognized as:n # any 3-tuple that starts or ends with a 2- or 4-digit year,n # with 2 or 0 separator chars (1.1.91 or 1191),n # maybe zero-padded (01-01-91 vs 1-1-91),n # a month between 1 and 12,n # a day between 1 and 31.n #n # note: this isn't true date parsing in that 'feb 31st' is allowed,n # this doesn't check for leap years, etc.n #n # recipe:n # start with regex to find maybe-dates, then attempt to map the integersn # onto month-day-year to filter the maybe-dates into dates.n # finally, remove matches that are substrings of other matches to reduce noise.n #n # note: instead of using a lazy or greedy regex to find many dates over the full string,n # this uses a ^...$ regex against every substring of the password -- less performant but leadsn # to every possible date match.n matches = []n maybe_date_no_separator = /^d{4,8}$/n maybe_date_with_separator = ///n ^n ( d{1,4} ) # day, month, yearn ( [s/_.-] ) # separatorn ( d{1,2} ) # day, monthn 2 # same separatorn ( d{1,4} ) # day, month, yearn $n ///nn # dates without separators are between length 4 '1191' and 8 '11111991'n for i in [0..password.length - 4]n for j in [i + 3..i + 7]n break if j >= password.lengthn token = password[i..j]n continue unless maybe_date_no_separator.exec tokenn candidates = []n for [k,l] in DATE_SPLITS[token.length]n dmy = @map_ints_to_dmy [n parseInt token[0...k]n parseInt token[k...l]n parseInt token[l...]n ]n candidates.push dmy if dmy?n continue unless candidates.length > 0n # at this point: different possible dmy mappings for the same i,j substring.n # match the candidate date that likely takes the fewest guesses: a year closest to 2000.n # (scoring.REFERENCE_YEAR).n #n # ie, considering '111504', prefer 11-15-04 to 1-1-1504n # (interpreting '04' as 2004)n best_candidate = candidates[0]n metric = (candidate) -> Math.abs candidate.year - scoring.REFERENCE_YEARn min_distance = metric candidates[0]n for candidate in candidates[1..]n distance = metric candidaten if distance < min_distancen [best_candidate, min_distance] = [candidate, distance]n matches.pushn pattern: 'date'n token: tokenn i: in j: jn separator: 'n year: best_candidate.yearn month: best_candidate.monthn day: best_candidate.daynn # dates with separators are between length 6 '1/1/91' and 10 '11/11/1991'n for i in [0..password.length - 6]n for j in [i + 5..i + 9]n break if j >= password.lengthn token = password[i..j]n rx_match = maybe_date_with_separator.exec tokenn continue unless rx_match?n dmy = @map_ints_to_dmy [n parseInt rx_match[1]n parseInt rx_match[3]n parseInt rx_match[4]n ]n continue unless dmy?n matches.pushn pattern: 'date'n token: tokenn i: in j: jn separator: rx_match[2]n year: dmy.yearn month: dmy.monthn day: dmy.daynn # matches now contains all valid date strings in a way that is tricky to capturen # with regexes only. 'matching = require './matching'nscoring = require './scoring'ntime_estimates = require './time_estimates'nfeedback = require './feedback'nntime = -> (new Date()).getTime()nnzxcvbn = (password, user_inputs = []) ->n start = time()n # reset the user inputs matcher on a per-request basis to keep things statelessn sanitized_inputs = []n for arg in user_inputsn if typeof arg in ['string', 'number', 'boolean']n sanitized_inputs.push arg.toString().toLowerCase()n matching.set_user_input_dictionary sanitized_inputsn matches = matching.omnimatch passwordn result = scoring.most_guessable_match_sequence password, matchesn result.calc_time = time() - startn attack_times = time_estimates.estimate_attack_times result.guessesn for prop, val of attack_timesn result[prop] = valn result.feedback = feedback.get_feedback result.score, result.sequencen resultnnmodule.exports = zxcvbnn'. No need to be fancy, just an overview. '# generated by scripts/build_keyboard_adjacency_graphs.pynadjacency_graphs = n qwerty: {'! ': ['0', '2', '3', null, null, null, null, null], '/': [null, null, null, null, '*', '9', '8', '7'], '0': [null, '1', '2', '3', '. Elite MILF Rayveness stopped by to see Swiney & give up both of her holes to. ', 'lL'], '|': ['=+', null, null, null, null, null], '}': ['[{', null, null, null, '=+', '/? ': [',<', 'lL', ';:', '/? Write something about yourself. She takes 3 huge loads of chubby cum as the Pigs empty their sacks on her tits. PASSwORD),n # the number of ways to lowercase U+L letters with L lowercase letters or less.n U = (chr for chr in word.split(') when chr.match /[A-Z]/).lengthn L = (chr for chr in word.split(') when chr.match /[a-z]/).lengthn variations = 0n variations += @nCk(U + L, i) for i in [1..Math.min(U, L)]n variationsnn l33t_variations: (match) ->n return 1 if not match.l33tn variations = 1n for subbed, unsubbed of match.subn # lower-case match.token before calculating: capitalization shouldn't affect l33t calc.n chrs = match.token.toLowerCase().split(')n S = (chr for chr in chrs when chr subbed).length # num of subbed charsn U = (chr for chr in chrs when chr unsubbed).length # num of unsubbed charsn if S 0 or U 0n # for this sub, password is either fully subbed (444) or fully unsubbed (aaa)n # treat that as doubling the space (attacker needs to try fully subbed chars in addition ton # unsubbed. ', '0', null], '3': ['2', '5', '6', '+', null, null, '. We have 171 full length hd movies with BBW HD Porn 1080p in our database available for free streaming. ', null, null], 'a': [null, '', ',<', 'oO', ';:', null], 'b': ['xX', 'dD', 'hH', 'mM', null, null], 'c': ['gG', '8*', '9(', 'rR', 'tT', 'hH'], 'd': ['iI', 'fF', 'gG', 'hH', 'bB', 'xX'], 'e': ['oO', '.>', 'pP', 'uU', 'jJ', 'qQ'], 'f': ['yY', '6^', '7&', 'gG', 'dD', 'iI'], 'g': ['fF', '7&', '8*', 'cC', 'hH', 'dD'], 'h': ['dD', 'gG', 'cC', 'tT', 'mM', 'bB'], 'i': ['uU', 'yY', 'fF', 'dD', 'xX', 'kK'], 'j': ['qQ', 'eE', 'uU', 'kK', null, null], 'k': ['jJ', 'uU', 'iI', 'xX', null, null], 'l': ['rR', '0)', '[{', '/? ', 'sS', 'nN'], 'm': ['bB', 'hH', 'tT', 'wW', null, null], 'n': ['tT', 'rR', 'lL', 'sS', 'vV', 'wW'], 'o': ['aA', ',<', '.>', 'eE', 'qQ', ';:'], 'p': ['.>', '4$', '5%', 'yY', 'uU', 'eE'], 'q': [';:', 'oO', 'eE', 'jJ', null, null], 'r': ['cC', '9(', '0)', 'lL', 'nN', 'tT'], 's': ['nN', 'lL', '/? src/public/js/zxcvbn.js This package implements a content management system with security features by default. )n # math is similar to extra guesses of l33t substitutions in dictionary matches.n if match.shifted_countn S = match.shifted_countn U = match.token.length - match.shifted_count # unshifted countn if S 0 or U 0n guesses *= 2n elsen shifted_variations = 0n shifted_variations += @nCk(S + U, i) for i in [1..Math.min(S, U)]n guesses *= shifted_variationsn guessesnn dictionary_guesses: (match) ->n match.base_guesses = match.rank # keep these as properties for display purposesn match.uppercase_variations = @uppercase_variations matchn match.l33t_variations = @l33t_variations matchn reversed_variations = match.reversed and 2 or 1n match.base_guesses * match.uppercase_variations * match.l33t_variations * reversed_variationsnn START_UPPER: /^[A-Z][^A-Z]+$/n END_UPPER: /^[^A-Z]+[A-Z]$/n ALL_UPPER: /^[^a-z]+$/n ALL_LOWER: /^[^A-Z]+$/nn uppercase_variations: (match) ->n word = match.tokenn return 1 if word.match(@ALL_LOWER) or word.toLowerCase() wordn # a capitalized word is the most common capitalization scheme,n # so it only doubles the search space (uncapitalized + capitalized).n # allcaps and end-capitalized are common enough too, underestimate as 2x factor to be safe.n for regex in [@START_UPPER, @END_UPPER, @ALL_UPPER]n return 2 if word.match regexn # otherwise calculate the number of ways to capitalize U+L uppercase+lowercase lettersn # with U uppercase letters or less. 'frequency_lists = require('./frequency_lists')nadjacency_graphs = require('./adjacency_graphs')nscoring = require('./scoring')nnbuild_ranked_dict = (ordered_list) ->n result = {}n i = 1 # rank starts at 1, not 0n for word in ordered_listn result[word] = in i += 1n resultnnRANKED_DICTIONARIES = {}nfor name, lst of frequency_listsn RANKED_DICTIONARIES[name] = build_ranked_dict lstnnGRAPHS =n qwerty: adjacency_graphs.qwertyn dvorak: adjacency_graphs.dvorakn keypad: adjacency_graphs.keypadn mac_keypad: adjacency_graphs.mac_keypadnnL33T_TABLE =n a: ['4', '@']n b: ['8']n c: ['(', '{', '[', '<']n e: ['3']n g: ['6', '9']n i: ['1', '! ', 'sS', 'nN'], 'M': ['bB', 'hH', 'tT', 'wW', null, null], 'N': ['tT', 'rR', 'lL', 'sS', 'vV', 'wW'], 'O': ['aA', ',<', '.>', 'eE', 'qQ', ';:'], 'P': ['.>', '4$', '5%', 'yY', 'uU', 'eE'], 'Q': [';:', 'oO', 'eE', 'jJ', null, null], 'R': ['cC', '9(', '0)', 'lL', 'nN', 'tT'], 'S': ['nN', 'lL', '/? ', ']}', null, '|', null, '-_'], ',': ['', '2@', '3#', '.>', 'oO', 'aA'], '-': ['sS', '/? ', '0'], '4': [null, null, '7', '8', '5', '2', '1', null], '5': ['4', '7', '8', '9', '6', '3', '2', '1'], '6': ['5', '8', '9', '-', '+', null, '3', '2'], '7': [null, null, null, '=', '8', '5', '4', null], '8': ['7', null, '=', '/', '9', '6', '5', '4'], '9': ['8', '=', '/', '*', '-', '+', '6', '5'], '=': [null, null, null, null, '/', '9', '8', '7']}nnmodule.exports = adjacency_graphsn'.
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