', '0'], '4': [null, null, '7', '8', '5', '2', '1', null], '5': ['4', '7', '8', '9', '6', '3', '2', '1'], '6': ['5', '8', '9', '+', null, null, '3', '2'], '7': [null, null, null, '/', '8', '5', '4', null], '8': ['7', null, '/', '*', '9', '6', '5', '4'], '9': ['8', '/', '*', '-', '+', null, '6', '5']}n mac_keypad: {'*': ['/', null, null, null, null, null, '-', '9'], '+': ['6', '9', '-', null, null, null, null, '3'], '-': ['9', '/', '*', null, null, null, '+', '6'], '. ', ']}', null, '|', null, '-_'], '>': [',<', '3#', '4$', 'pP', 'eE', 'oO'], '? Watch BBW HD Porn 1080p HD porn videos for free on Eporner.com. '# generated by scripts/build_keyboard_adjacency_graphs.pynadjacency_graphs = n qwerty: {'! )n variations *= 2n elsen # this case is similar to capitalization:n # with aa44a, U = 3, S = 2, attacker needs to try unsubbed + one sub + two subsn p = Math.min(U, S)n possibilities = 0n possibilities += @nCk(U + S, i) for i in [1..p]n variations *= possibilitiesn variationsnn # utilities --------------------------------------------------------------------nnmodule.exports = scoringn', 'time_estimates =n estimate_attack_times: (guesses) ->n crack_times_seconds =n online_throttling_100_per_hour: guesses / (100 / 3600)n online_no_throttling_10_per_second: guesses / 10n offline_slow_hashing_1e4_per_second: guesses / 1e4n offline_fast_hashing_1e10_per_second: guesses / 1e10nn crack_times_display = {}n for scenario, seconds of crack_times_secondsn crack_times_display[scenario] = @display_time secondsnn crack_times_seconds: crack_times_secondsn crack_times_display: crack_times_displayn score: @guesses_to_score guessesnnn guesses_to_score: (guesses) ->n DELTA = 5n if guesses < 1e3 + DELTAn # risky password: 'too guessable'n 0n else if guesses < 1e6 + DELTAn # modest protection from throttled online attacks: 'very guessable'n 1n else if guesses < 1e8 + DELTAn # modest protection from unthrottled online attacks: 'somewhat guessable'n 2n else if guesses < 1e10 + DELTAn # modest protection from offline attacks: 'safely unguessable'n # assuming a salted, slow hash function like bcrypt, scrypt, PBKDF2, argon, etcn 3n elsen # strong protection from offline attacks under same scenario: 'very unguessable'n 4nn display_time: (seconds) ->n minute = 60n hour = minute * 60n day = hour * 24n month = day * 31n year = month * 12n century = year * 100n [display_num, display_str] = if seconds < 1n [null, 'less than a second']n else if seconds < minuten base = Math.round secondsn [base, '#{base} second']n else if seconds < hourn base = Math.round seconds / minuten [base, '#{base} minute']n else if seconds < dayn base = Math.round seconds / hourn [base, '#{base} hour']n else if seconds < monthn base = Math.round seconds / dayn [base, '#{base} day']n else if seconds < yearn base = Math.round seconds / monthn [base, '#{base} month']n else if seconds < centuryn base = Math.round seconds / yearn [base, '#{base} year']n elsen [null, 'centuries']n display_str += 's' if display_num? '], '^': ['5%', null, null, '7&', 'fF', 'yY'], '_': ['sS', '/? ', '0'], '4': [null, null, '7', '8', '5', '2', '1', null], '5': ['4', '7', '8', '9', '6', '3', '2', '1'], '6': ['5', '8', '9', '-', '+', null, '3', '2'], '7': [null, null, null, '=', '8', '5', '4', null], '8': ['7', null, '=', '/', '9', '6', '5', '4'], '9': ['8', '=', '/', '*', '-', '+', '6', '5'], '=': [null, null, null, null, '/', '9', '8', '7']}nnmodule.exports = adjacency_graphsn'. '], '#': ['2@', null, null, '4$', 'eE', 'wW'], '$': ['3#', null, null, '5%', 'rR', 'eE'], '%': ['4$', null, null, '6^', 'tT', 'rR'], '&': ['6^', null, null, '8*', 'uU', 'yY'], '': [';:', '[{', ']}', null, null, '/? l_max is the maximum optimaln # sequence length spanning each prefix of the password. ', 'sS', 'nN'], 'M': ['bB', 'hH', 'tT', 'wW', null, null], 'N': ['tT', 'rR', 'lL', 'sS', 'vV', 'wW'], 'O': ['aA', ',<', '.>', 'eE', 'qQ', ';:'], 'P': ['.>', '4$', '5%', 'yY', 'uU', 'eE'], 'Q': [';:', 'oO', 'eE', 'jJ', null, null], 'R': ['cC', '9(', '0)', 'lL', 'nN', 'tT'], 'S': ['nN', 'lL', '/? ', null, null], 'a': [null, '', ',<', 'oO', ';:', null], 'b': ['xX', 'dD', 'hH', 'mM', null, null], 'c': ['gG', '8*', '9(', 'rR', 'tT', 'hH'], 'd': ['iI', 'fF', 'gG', 'hH', 'bB', 'xX'], 'e': ['oO', '.>', 'pP', 'uU', 'jJ', 'qQ'], 'f': ['yY', '6^', '7&', 'gG', 'dD', 'iI'], 'g': ['fF', '7&', '8*', 'cC', 'hH', 'dD'], 'h': ['dD', 'gG', 'cC', 'tT', 'mM', 'bB'], 'i': ['uU', 'yY', 'fF', 'dD', 'xX', 'kK'], 'j': ['qQ', 'eE', 'uU', 'kK', null, null], 'k': ['jJ', 'uU', 'iI', 'xX', null, null], 'l': ['rR', '0)', '[{', '/? ', '.>'], '<': ['mM', 'kK', 'lL', '.>', null, null], '=': ['-_', null, null, null, ']}', '[{'], '>': [',<', 'lL', ';:', '/? (% instead of 5, A instead of a. Verwalten Sie schnell und effektiv Ihr Arztprofil auf aerzte.de über unseren Kundenbereich. ', '-_', 'zZ', 'vV'], 't': ['hH', 'cC', 'rR', 'nN', 'wW', 'mM'], 'u': ['eE', 'pP', 'yY', 'iI', 'kK', 'jJ'], 'v': ['wW', 'nN', 'sS', 'zZ', null, null], 'w': ['mM', 'tT', 'nN', 'vV', null, null], 'x': ['kK', 'iI', 'dD', 'bB', null, null], 'y': ['pP', '5%', '6^', 'fF', 'iI', 'uU'], 'z': ['vV', 'sS', '-_', null, null, null], '{': ['0)', null, null, ']}', '/? ', '.>'], ';': ['lL', 'pP', '[{', '', '/? ': ['`~', null, null, '2@', '', null], '': [null, '1! ', null, null, '3#', ',<', ''], 'A': [null, '', ',<', 'oO', ';:', null], 'B': ['xX', 'dD', 'hH', 'mM', null, null], 'C': ['gG', '8*', '9(', 'rR', 'tT', 'hH'], 'D': ['iI', 'fF', 'gG', 'hH', 'bB', 'xX'], 'E': ['oO', '.>', 'pP', 'uU', 'jJ', 'qQ'], 'F': ['yY', '6^', '7&', 'gG', 'dD', 'iI'], 'G': ['fF', '7&', '8*', 'cC', 'hH', 'dD'], 'H': ['dD', 'gG', 'cC', 'tT', 'mM', 'bB'], 'I': ['uU', 'yY', 'fF', 'dD', 'xX', 'kK'], 'J': ['qQ', 'eE', 'uU', 'kK', null, null], 'K': ['jJ', 'uU', 'iI', 'xX', null, null], 'L': ['rR', '0)', '[{', '/? * Product(m.guesses for m in sequence) + D^(l - 1)n #n # where l is the length of the sequence.n #n # the factorial term is the number of ways to order l patterns.n #n # the D^(l-1) term is another length penalty, roughly capturing the idea that ann # attacker will try lower-length sequences first before trying length-l sequences.n #n # for example, consider a sequence that is date-repeat-dictionary.n # - an attacker would need to try other date-repeat-dictionary combinations,n # hence the product term.n # - an attacker would need to try repeat-date-dictionary, dictionary-repeat-date,n # ..., hence the factorial term.n # - an attacker would also likely try length-1 (dictionary) and length-2 (dictionary-date)n # sequences before length-3. ', 'lL'], '|': ['=+', null, null, null, null, null], '}': ['[{', null, null, null, '=+', '/? ', '0', null], '3': ['2', '5', '6', '+', null, null, '. ', null, null, '3#', ',<', ''], '3': ['2@', null, null, '4$', '.>', ',<'], '4': ['3#', null, null, '5%', 'pP', '.>'], '5': ['4$', null, null, '6^', 'yY', 'pP'], '6': ['5%', null, null, '7&', 'fF', 'yY'], '7': ['6^', null, null, '8*', 'gG', 'fF'], '8': ['7&', null, null, '9(', 'cC', 'gG'], '9': ['8*', null, null, '0)', 'rR', 'cC'], ':': [null, 'aA', 'oO', 'qQ', null, null], ';': [null, 'aA', 'oO', 'qQ', null, null], '<': ['', '2@', '3#', '.>', 'oO', 'aA'], '=': ['/? )1+$/n lastIndex = 0n while lastIndex < password.lengthn greedy.lastIndex = lazy.lastIndex = lastIndexn greedy_match = greedy.exec passwordn lazy_match = lazy.exec passwordn break unless greedy_match?n if greedy_match[0].length > lazy_match[0].lengthn # greedy beats lazy for 'aabaab'n # greedy: [aabaab, aab]n # lazy: [aa, a]n match = greedy_matchn # greedy's repeated string might itself be repeated, eg.n # aabaab in aabaabaabaab.n # run an anchored lazy match on greedy's repeated stringn # to find the shortest repeated stringn base_token = lazy_anchored.exec(match[0])[1]n elsen # lazy beats greedy for 'aaaaa'n # greedy: [aaaa, aa]n # lazy: [aaaaa, a]n match = lazy_matchn base_token = match[1]n [i, j] = [match.index, match.index + match[0].length - 1]n # recursively match and score the base stringn base_analysis = scoring.most_guessable_match_sequence(n base_tokenn @omnimatch base_tokenn )n base_matches = base_analysis.sequencen base_guesses = base_analysis.guessesn matches.pushn pattern: 'repeat'n i: in j: jn token: match[0]n base_token: base_tokenn base_guesses: base_guessesn base_matches: base_matchesn repeat_count: match[0].length / base_token.lengthn lastIndex = j + 1n matchesnn MAX_DELTA: 5n sequence_match: (password) ->n # Identifies sequences by looking for repeated differences in unicode codepoint.n # this allows skipping, such as 9753, and also matches some extended unicode sequencesn # such as Greek and Cyrillic alphabets.n #n # for example, consider the input 'abcdb975zy'n #n # password: a b c d b 9 7 5 z yn # index: 0 1 2 3 4 5 6 7 8 9n # delta: 1 1 1 -2 -41 -2 -2 69 1n #n # expected result:n # [(i, j, delta), ...] = [(0, 3, 1), (5, 7, -2), (8, 9, 1)]nn return [] if password.length 1nn update = (i, j, delta) =>n if j - i > 1 or Math.abs(delta) 1n if 0 < Math.abs(delta) <= @MAX_DELTAn token = password[i..j]n if /^[a-z]+$/.test(token)n sequence_name = 'lower'n sequence_space = 26n else if /^[A-Z]+$/.test(token)n sequence_name = 'upper'n sequence_space = 26n else if /^d+$/.test(token)n sequence_name = 'digits'n sequence_space = 10n elsen # conservatively stick with roman alphabet size.n # (this could be improved)n sequence_name = 'unicode'n sequence_space = 26n result.pushn pattern: 'sequence'n i: in j: jn token: password[i..j]n sequence_name: sequence_namen sequence_space: sequence_spacen ascending: delta > 0nn result = []n i = 0n last_delta = nullnn for k in [1...password.length]n delta = password.charCodeAt(k) - password.charCodeAt(k - 1)n unless last_delta?n last_delta = deltan continue if delta last_deltan j = k - 1n update(i, j, last_delta)n i = jn last_delta = deltan update(i, password.length - 1, last_delta)n resultnn #-------------------------------------------------------------------------------n # regex matching ---------------------------------------------------------------n #-------------------------------------------------------------------------------nn regex_match: (password, _regexen = REGEXEN) ->n matches = []n for name, regex of _regexenn regex.lastIndex = 0 # keeps regex_match statelessn while rx_match = regex.exec passwordn token = rx_match[0]n matches.pushn pattern: 'regex'n token: tokenn i: rx_match.indexn j: rx_match.index + rx_match[0].length - 1n regex_name: namen regex_match: rx_matchn @sorted matchesnn #-------------------------------------------------------------------------------n # date matching ----------------------------------------------------------------n #-------------------------------------------------------------------------------nn date_match: (password) ->n # a 'date' is recognized as:n # any 3-tuple that starts or ends with a 2- or 4-digit year,n # with 2 or 0 separator chars (1.1.91 or 1191),n # maybe zero-padded (01-01-91 vs 1-1-91),n # a month between 1 and 12,n # a day between 1 and 31.n #n # note: this isn't true date parsing in that 'feb 31st' is allowed,n # this doesn't check for leap years, etc.n #n # recipe:n # start with regex to find maybe-dates, then attempt to map the integersn # onto month-day-year to filter the maybe-dates into dates.n # finally, remove matches that are substrings of other matches to reduce noise.n #n # note: instead of using a lazy or greedy regex to find many dates over the full string,n # this uses a ^...$ regex against every substring of the password -- less performant but leadsn # to every possible date match.n matches = []n maybe_date_no_separator = /^d{4,8}$/n maybe_date_with_separator = ///n ^n ( d{1,4} ) # day, month, yearn ( [s/_.-] ) # separatorn ( d{1,2} ) # day, monthn 2 # same separatorn ( d{1,4} ) # day, month, yearn $n ///nn # dates without separators are between length 4 '1191' and 8 '11111991'n for i in [0..password.length - 4]n for j in [i + 3..i + 7]n break if j >= password.lengthn token = password[i..j]n continue unless maybe_date_no_separator.exec tokenn candidates = []n for [k,l] in DATE_SPLITS[token.length]n dmy = @map_ints_to_dmy [n parseInt token[0...k]n parseInt token[k...l]n parseInt token[l...]n ]n candidates.push dmy if dmy?n continue unless candidates.length > 0n # at this point: different possible dmy mappings for the same i,j substring.n # match the candidate date that likely takes the fewest guesses: a year closest to 2000.n # (scoring.REFERENCE_YEAR).n #n # ie, considering '111504', prefer 11-15-04 to 1-1-1504n # (interpreting '04' as 2004)n best_candidate = candidates[0]n metric = (candidate) -> Math.abs candidate.year - scoring.REFERENCE_YEARn min_distance = metric candidates[0]n for candidate in candidates[1..]n distance = metric candidaten if distance < min_distancen [best_candidate, min_distance] = [candidate, distance]n matches.pushn pattern: 'date'n token: tokenn i: in j: jn separator: 'n year: best_candidate.yearn month: best_candidate.monthn day: best_candidate.daynn # dates with separators are between length 6 '1/1/91' and 10 '11/11/1991'n for i in [0..password.length - 6]n for j in [i + 5..i + 9]n break if j >= password.lengthn token = password[i..j]n rx_match = maybe_date_with_separator.exec tokenn continue unless rx_match?n dmy = @map_ints_to_dmy [n parseInt rx_match[1]n parseInt rx_match[3]n parseInt rx_match[4]n ]n continue unless dmy?n matches.pushn pattern: 'date'n token: tokenn i: in j: jn separator: rx_match[2]n year: dmy.yearn month: dmy.monthn day: dmy.daynn # matches now contains all valid date strings in a way that is tricky to capturen # with regexes only.

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